Answer on Mechanics | Relativity Question for Melanie
F = 102 N
M = 70.0 kg
α = 17°
μ = 0.200
d = 8 m
The horizontal projection of the pulling force is
Fh = F*cosα = 102*cos(17) = 97,543 N.
Fv = F*sinα = 102*sin(17) = 29,822 N.
The friction force is:
Ffr = Fn*μ = (M*g-Fv)*μ = (102*9.8-29,822)*0.2 = 193,956 N.
Here Fn is the normal reaction force.
So, we see that for given conditions the pulling force is too weak to displace the refrigerator. Please check the input values, maybe the friction coefficient is less or refrigirator is lighter?
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