# Answer to Question #4938 in Mechanics | Relativity for Nancy

Question #4938

After 10 s an object is displaced 40 m [W] due to a uniform acceleration of - 5 m/s squared. What is the object's final velocity?

Expert's answer

Let's find the initial velocity Vi of an object. We know that

Vi*t + (a*t^2)/2 = d

So, Vi = (d - (a*t^2)/2)/t = d/t + a*t/2 = 40/10 + 5*10/2 = 29 m/s.

Now we can find the object's final velocity Vf:

Vf = Vi + a*t = 29 + 5*10 = 79 m/s.

Vi*t + (a*t^2)/2 = d

So, Vi = (d - (a*t^2)/2)/t = d/t + a*t/2 = 40/10 + 5*10/2 = 29 m/s.

Now we can find the object's final velocity Vf:

Vf = Vi + a*t = 29 + 5*10 = 79 m/s.

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