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# Answer to Question #4962 in Mechanics | Relativity for yamini

Question #4962
6 particles situated at the corners of a regular hexagon of side 'a' move at a constant speed 'v'. each particle maintains a direction towards the particle at the next corner. the time taken 't' by the particles to meet each other is ?
1
2011-11-04T11:42:15-0400
Let us concentrate on two particles say A and B only.
Initial separation between two particles = side of the hexagon=a
Final separation =0
Thus, relative displacement between two particles =a.
Particle B has a component of velocity v cos 60& along AB
Thus, relative velocity with which A approaches B is v-vcos 60=v/2
As v is uniform& time taken by theese two particles to meet = relative displacement/relative velocity =a/(v/2)=2a/v
Hence the time taken by particles to meet each other =2a/v - answer

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