# Answer to Question #4873 in Mechanics | Relativity for yasmina

Question #4873

A boat moves through the water with two forces acting on it. One is a 2.72×10 3 N forward push by the motor, and the other is a 1.76×10 3 N resistive force due to the water. What is the acceleration of the 1384.9 kg boat? Answer in units of m/s 2 If it starts from rest, how far will it move in 17.3 s? Answer in units of m

Expert's answer

Due to Newton's second law:

Fm - Fres = ma

where Fm is the force which

motor pushes and Fres is a resistive force.

a = (Fm - Fres)/m =

(2.72*10^3 - 1.76*10^3) / 1384.9 = 0.693 m/s^2.

The equation for displacement

is:

S = V0*t & + (at^2)/2, V0 = 0.

S = (at^2)/2 = (0.693*17.3^2)/2 = 103.7

m

Fm - Fres = ma

where Fm is the force which

motor pushes and Fres is a resistive force.

a = (Fm - Fres)/m =

(2.72*10^3 - 1.76*10^3) / 1384.9 = 0.693 m/s^2.

The equation for displacement

is:

S = V0*t & + (at^2)/2, V0 = 0.

S = (at^2)/2 = (0.693*17.3^2)/2 = 103.7

m

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