Answer to Question #4808 in Mechanics | Relativity for rita
500-F = 25a (1)
The average speed of an object is
(60+40)/2 = 50 m/s.
So, moving time T:
T = 100/50 = 2 s.
Let's find the acceleration of an object:
a = (60-40)/T = 20/2 = 10 m/s^2.
From (1) we obtain:
F = 500-25a = 500-25*10 = 250 N.
So, the friction force has value 250N.
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