Question #4806

A young boy swings a yo-yo horizontally above his head so that the yo-yo has a cen- tripetal acceleration of 250 m/s2.
If the yo-yo’s string is 0.14 m long, what is the yo-yo’s tangential speed?
Answer in units of m/s

Expert's answer

Tangential speed Vt=omega * R

where R=0.14 m - the yo-yo’s string

omega - angular velocity of the yo-yo

centripetal acceleration Wc=omega^2 *R

=> omega=sqrt(Wc/R)=sqrt(250/0.14)=42.25

Hence Vt=omega*R=42.25*0.14=5.91 m/s

where R=0.14 m - the yo-yo’s string

omega - angular velocity of the yo-yo

centripetal acceleration Wc=omega^2 *R

=> omega=sqrt(Wc/R)=sqrt(250/0.14)=42.25

Hence Vt=omega*R=42.25*0.14=5.91 m/s

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