Answer to Question #25365 in Mechanics | Relativity for Karthi
A = U2 - U1
A - work which the weightlifter do,
U1, U2 - initial and final potential energies
U = mgh - the definition of the potential energy
m - mass
g - gravitational acceleration
h - high
At the beginning, the weightlifter was staying on the ground, so h=0.
A = mgh - mg*0 = mgh
A = 32*2.2*9.8 = 689.92 J
Answer: 689.92 J
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