# Answer to Question #1244 in Mechanics | Relativity for Jessica

Question #1244

A juggler throws a ball from height of 0.950 m with a vertical velocity of +3.50 m/s and misses it on the way down. What is its velocity when it hits the ground?

Expert's answer

According to the equations of the motion:

h = h

v = v

h

v

h = 0

0 = 0.95 +3.5t - 10t

5t

D = 3.5

t

t

v = 3.5 - 0.91*10 = -5.6 m/s

Answer:

The velocity would be equal to 5.6 m/s and its vector is directed downward.

h = h

_{0}+v_{0}t - gt^{2}/2;v = v

_{0}- gt.h

_{0}= 0.95v

_{0}= 3.5 m/sh = 0

0 = 0.95 +3.5t - 10t

^{2}/25t

^{2}- 3.5t - 0.95 = 0D = 3.5

^{2}+ 5*0.95*4 = 31.25t

_{1}= (3.5+5.6) / 10 = 0.91t

_{2}= -0.21 - out of sense.v = 3.5 - 0.91*10 = -5.6 m/s

Answer:

The velocity would be equal to 5.6 m/s and its vector is directed downward.

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