Answer to Question #1244 in Mechanics | Relativity for Jessica
Question #1244
A juggler throws a ball from height of 0.950 m with a vertical velocity of +3.50 m/s and misses it on the way down. What is its velocity when it hits the ground?
Expert's answer
According to the equations of the motion:
h = h0 +v0t - gt2/2;
v = v0 - gt.
h0 = 0.95
v0 = 3.5 m/s
h = 0
0 = 0.95 +3.5t - 10t2/2
5t2 - 3.5t - 0.95 = 0
D = 3.52 + 5*0.95*4 = 31.25
t1 = (3.5+5.6) / 10 = 0.91
t2 = -0.21 - out of sense.
v = 3.5 - 0.91*10 = -5.6 m/s
Answer:
The velocity would be equal to 5.6 m/s and its vector is directed downward.
h = h0 +v0t - gt2/2;
v = v0 - gt.
h0 = 0.95
v0 = 3.5 m/s
h = 0
0 = 0.95 +3.5t - 10t2/2
5t2 - 3.5t - 0.95 = 0
D = 3.52 + 5*0.95*4 = 31.25
t1 = (3.5+5.6) / 10 = 0.91
t2 = -0.21 - out of sense.
v = 3.5 - 0.91*10 = -5.6 m/s
Answer:
The velocity would be equal to 5.6 m/s and its vector is directed downward.
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