Question #1244

A juggler throws a ball from height of 0.950 m with a vertical velocity of +3.50 m/s and misses it on the way down. What is its velocity when it hits the ground?

Expert's answer

According to the equations of the motion:

h = h_{0} +v_{0}t - gt^{2}/2;

v = v_{0} - gt.

h_{0} = 0.95

v_{0} = 3.5 m/s

h = 0

0 = 0.95 +3.5t - 10t^{2}/2

5t^{2} - 3.5t - 0.95 = 0

D = 3.5^{2} + 5*0.95*4 = 31.25

t_{1} = (3.5+5.6) / 10 = 0.91

t_{2} = -0.21 - out of sense.

v = 3.5 - 0.91*10 = -5.6 m/s

Answer:

The velocity would be equal to 5.6 m/s and its vector is directed downward.

h = h

v = v

h

v

h = 0

0 = 0.95 +3.5t - 10t

5t

D = 3.5

t

t

v = 3.5 - 0.91*10 = -5.6 m/s

Answer:

The velocity would be equal to 5.6 m/s and its vector is directed downward.

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