Answer to Question #1227 in Mechanics | Relativity for kayna
h= h0 +v0t +at2/2
where v0 = 0;
h0 = 17.5 m, v0 = 0, a = -9.8 m/s2;
0 = 17.5 - 9.8t2/2
t = 1.89 s.
b) the horizontal motion is constant with the velocity of 125 m/s, thus the distance would be
S = Vt = 125*1.89 = 236.23 m/s.
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