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Answer on Mechanics | Relativity Question for danica

Question #1240
Sam tosses a ball horizontally off a footbridge at 3.1 m/s. How much time passes after he releases it until its speed doubles?
Expert's answer
The horizontal projection is constant while the vertical is changing according to the equation
(we chose the downward direction as positive).
Vx = 3.1 m/s
V0y = 0;
V0 = 3.1 m/s
V = √(Vx2 + Vy2) = √(3.12 +100t2)
V2/V02 = 4
(3.12 +100t2)/ 3.12 = 4
t =√(3.12*3 / 100) = 0.54 s

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