Answer to Question #121770 in Mechanics | Relativity for favour

Question #121770
A student is given a spring balance that has a scale in newtons. The student is told that the acceleration of free-fall is 10 m/s2. (i) Describe how the student could find the mass of an irregular solid object.
Expert's answer

Explanations & Calculations

  • Acceleration of free fall is known as the gravity of that particular area.
  • The product of that acceleration & the mass of a given object gives the weight of that object relative to that area.
  • When a measurement is obtained using that spring balance, it's the weight of that object being measured.

"\\qquad\\qquad\n\\begin{aligned}\n\\small \\text{Weight (N)} &= \\small \\text{Mass(kg)} \\times \\text{F.f.acceleration}(ms^{-2})\\\\\n\\small \\therefore \\text{Mass} &= \\small \\frac{\\text{Weight}}{\\text{Free fall Acceleration}}\n\\end{aligned}"

  • Student can measure the weight of that object by hanging it to the spring balance by means of a string. (weight of the string used should be negligible compared to that of the object)
  • Then mass is calculated by the above relationship.

  • Or to be more accurate, the weight of the string used could be measured first.(Wstring).
  • Then get the total weight (Wtotal = Wstring + Wobject).
  • Then Wobject could be calculated & followed the other steps.

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