Answer to Question #121487 in Mechanics | Relativity for Muhammad Shahzad

Question

Data:
length of pendulum =l=0.5m
acceleration =g=9.8m/s²
To find:
frequency =?

Answer 1

Given data,

Length of pendulum is $l=0.5m$

Acceleration due to gravity $g=9.8m/s^2$

Since,

$$T=2\pi\sqrt{\frac{l}{g}}\\ \implies \nu=\frac{1}{T}=\frac{1}{2\pi}\sqrt{\frac{g}{l}}$$

Thus,

$$\nu=\frac{1}{2\pi}\sqrt{\frac{9.8}{0.5}}=0.70Hz$$