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# Answer to Question #121538 in Mechanics | Relativity for isaac

Question #121538
What mass should be hung on an elastic material of stiffness 100N/m to produce an extension of 20cm.
1
2020-06-11T10:33:17-0400

By the definition of the Hooke's Law, we get:

"F = kx,"

here, "F" is the force acting on the elastic material, "k" is the stiffness of the material, "x" is the extension of the material.

From the other hand, "F = mg" (when the mass is attached), and substituting it into the first equation we get :

"mg = kx,""m = \\dfrac{kx}{g},""m = \\dfrac{100 \\ \\dfrac{N}{m} \\cdot 0.2 \\ m}{9.8 \\ \\dfrac{m}{s^2}} = 2.04 kg."

"m = 2.04 kg."

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