Answer to Question #1905 in Astronomy | Astrophysics for nirmala
GmM/r2, where G - gravity constant, m - satellite mass, M - Earth mass.
Due to second Newton's Law gravitation force = centripetal force mv2/r.
Hence we obtain the expression for the velocity of satellite:
Period Tсп = circumference of the orbit, 2π r, divided by the satellite velocity v:
Tсп=2π r/v=2π (r3/GM)1/2
A geosynchronous orbit (sometimes abbreviated GSO) is an orbit around the Earth with an orbital period that matches the Earth's sidereal rotation period.The synchronization of rotation and orbital period means that for an observer on the surface of the Earth, the satellite appears to constantly hover over the same meridian (north-south line) on the surface, moving in a slow oscillation alternately north and south with a period of one day, so it returns to exactly the same place in the sky at exactly the same time each day
Earth's sidereal rotation period = 23 hours 56 min 4.1 s=86164.1 s
Altitude H=(T*R*√(G)/2π)2/3 - R
where R-Earth radius, R=6370 km
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