# Answer to Question #1381 in Astronomy | Astrophysics for chucky

Question #1381

In order to escape a planet's orbit, an object must

Expert's answer

The object must have the velocity at which the sum of kinetic and its gravitational potential energy is equal to zero (escape velocity).

Thus

mv

v = √(2GM/R)

Thus

mv

^{2}/2 - G mM/R = 0, where G - is gravitational constant, M - the mass of the planet, R - is the orbit of the moving object, m - is the mass of the object.v = √(2GM/R)

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