57 408
Assignments Done
99%
Successfully Done
In February 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.

# Answer on Calculus Question for noor

Question #3691
What is the integral of tan^-1(4x) dx ?
&lt;img src=&quot;/cgi-bin/mimetex.cgi?%5Cint%7B%5Ctan%5E%7B-1%7D%284x%29dx%7D%20=%20[%5Carctan%284x%29%20=%20u,%20du%20=%20%5Cfrac%7B4%7D%7B16x%5E2%20+%201%7D,%20x=%20dv,%20v%20=%20dx]%20=%20%5C%5C%20=%20x%20%5Carctan%284x%29%20-%20%5Cint%7B%5Cfrac%7B4xdx%7D%7B16x%5E2%20+%201%7D%7D%20=%20x%20%5Carctan%284x%29%20-%20%5Cint%7B%5Cfrac%7B2dx%5E2%7D%7B16x%5E2%20+%201%7D%7D%20=%20%5C%5C%20=%20x%20%5Carctan%284x%29%20-%20%5Cfrac%7B1%7D%7B8%7D%5Cln%2816x%5E2%20+%201%29&quot; title=&quot;\int{\tan^{-1}(4x)dx} = [\arctan(4x) = u, du = \frac{4}{16x^2 + 1}, x= dv, v = dx] = \\ = x \arctan(4x) - \int{\frac{4xdx}{16x^2 + 1}} = x \arctan(4x) - \int{\frac{2dx^2}{16x^2 + 1}} = \\ = x \arctan(4x) - \frac{1}{8}\ln(16x^2 + 1)&quot;&gt;

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!