Question #3431

The equation for a projectile's height versus time is h(t)=-16t^2+vt+h
A tennis ball machine serves a ball vertically into the air from a height of feet, with an initial speed of 130 feet per second. What is the maximum height,in feet, the ball will attain

Expert's answer

Let's take the first derivative:

h'(t) = -32t +v.

The maximum height is obtained when h'(t) = 0:

-32t = -v

t = v/32

t = 130/32 = 4.0625 s

h(4.0625) = -16 (4.0625)2 + 130 *4.0625 +0 = 264.0625 ft.

h'(t) = -32t +v.

The maximum height is obtained when h'(t) = 0:

-32t = -v

t = v/32

t = 130/32 = 4.0625 s

h(4.0625) = -16 (4.0625)2 + 130 *4.0625 +0 = 264.0625 ft.

## Comments

Assignment Expert29.03.16, 15:03Dear Keshia Wilson.

The first derivative of (-16t^2+vt+h) with respect to t is equal to (-32t+v).

Keshia Wilson28.03.16, 08:52Where did you get 32 from? On my paper height equal 2/

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