Answer to Question #1524 in Calculus for nate
f(x) = x^2 + 3x / 2x^2 + 6x + 4
f(x) = (x^2 + 3x )/( 2x^2 + 6x + 4) = x(x+3)/2(x+1)(x+2)
f(x) = 0 at x=0 and x=3, f(x) doesn't exist at x = -1 and x = -2.
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