# Answer to Question #6304 in Algebra for Brandy

Question #6304

Determine the number of standard deviations which include all data values listed for the situation. The mean height of a tree in an orchard is 11.8 feet; the standard deviation is 1.43 feet.

12.5 ft, 9.8 ft, 13.5 ft, 11.2 ft, 12.3 ft, 14.2 ft, 11.7 ft, 9.8 ft, 12.6 ft, 10.4 ft

12.5 ft, 9.8 ft, 13.5 ft, 11.2 ft, 12.3 ft, 14.2 ft, 11.7 ft, 9.8 ft, 12.6 ft, 10.4 ft

Expert's answer

standard deviation for all values

((12.5-11.8)^2+(9.8-11.8)^2+(13.5-11.8)^2+(11.2-11.8)^2+(12.3-11.8)^2+(14.2-11.8)^2+(11.7-11.8)^2+(9.8-11.8)^2+(12.6-11.8)^2+(10.4-11.8)^2)/10=2.036

((12.5-11.8)^2+(9.8-11.8)^2+(13.5-11.8)^2+(11.2-11.8)^2+(12.3-11.8)^2+(14.2-11.8)^2+(11.7-11.8)^2+(9.8-11.8)^2+(12.6-11.8)^2+(10.4-11.8)^2)/10=2.036

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