Answer to Question #6299 in Algebra for Brandy
Question #6299
Solve 3 cos θ = cos θ - √2 for 0 <= θ < 2π
Expert's answer
3 cos θ = cos θ - √2 ; 0 <= θ < 2π
2 cos θ = - √2
cos θ = - √2 / 2 then, taking in account that 0 <= θ < 2π
θ = 3π / 4 or θ = 5π / 4
2 cos θ = - √2
cos θ = - √2 / 2 then, taking in account that 0 <= θ < 2π
θ = 3π / 4 or θ = 5π / 4
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