# Answer to Question #6299 in Algebra for Brandy

Question #6299

Solve 3 cos θ = cos θ - √2 for 0 <= θ < 2π

Expert's answer

3 cos θ = cos θ - √2 ; 0 <= θ < 2π

2 cos θ = - √2

cos θ = - √2 / 2 then, taking in account that 0 <= θ < 2π

θ = 3π / 4 or θ = 5π / 4

2 cos θ = - √2

cos θ = - √2 / 2 then, taking in account that 0 <= θ < 2π

θ = 3π / 4 or θ = 5π / 4

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