Question #6298

Solve cot θ sin θ = 1/2 for 0 <= θ < 2π.

Expert's answer

cot(theta)*sin(theta) = 1/2.

cot(theta) = cos(theta)/sin(theta), sin(theta)

is not zero. So:

cos(theta)/sin(theta)*sin(theta) = 1/2.

cos(theta) =

1/2.

As theta is from [0,2*pi], then

theta = pi/3 or theta = 5pi/3.

cot(theta) = cos(theta)/sin(theta), sin(theta)

is not zero. So:

cos(theta)/sin(theta)*sin(theta) = 1/2.

cos(theta) =

1/2.

As theta is from [0,2*pi], then

theta = pi/3 or theta = 5pi/3.

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