The circuit shown in Fig.5 is applied with a 240 V, 50 Hz supply. Find thevalues of R and C so thatVb=3Va and Vb and Va are in phase quadrature
Angle between V and I
The angle between Vs and Vb = 18.43°
In the phasor diagram, I have been taken as a reference. Vb is in the first quadrant. Hence Va must be in the fourth quadrant since Za consists of R and Xc. The angle between Va and I is then 36.87°.
Since Za and Zb are in series, V is represented by the phasor OD which is at an angle of
Thus, the circuit has a total effective impedance of 10.53 ohms.
In the phasor diagram,
Hence, Va = OE = 3.33 I,
Since BOE =
Horizontal component of
Vertical component of
Hence, the total impedance =
Angle between Vs and I =