Question #199869

The circuit shown in Fig.5 is applied with a 240 V, 50 Hz supply. Find thevalues of R and C so thatVb=3Va and Vb and Va are in phase quadrature

Expert's answer

Angle between V and I

The angle between Vs and Vb = 18.43°

In the phasor diagram, I have been taken as a reference. Vb is in the first quadrant. Hence Va must be in the fourth quadrant since Za consists of R and Xc. The angle between Va and I is then 36.87°.

Since Za and Zb are in series, V is represented by the phasor OD which is at an angle of

Thus, the circuit has a total effective impedance of 10.53 ohms.

In the phasor diagram,

Hence, Va = OE = 3.33 I,

Since BOE =

Hence,

Hence

Horizontal component of

Vertical component of

Hence, the total impedance =

Angle between Vs and I =

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