Answer to Question #231018 in Chemical Engineering for Lucky

Question #231018

1)For the reaction A products, the temperature is increased from 300°C to 500°C, and then the times of reaction have been doubled What is the activation energy for the particular reaction? (se Arthenius theory)


1
Expert's answer
2021-09-06T00:54:21-0400

The activation energy can be determined using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

where

Ea = the activation energy of the reaction in J/mol

R = the ideal gas constant = 8.3145 J/K·mol

T1 and T2 = absolute temperatures (in Kelvin)

k1 and k2 = the reaction rate constants at T1 and T2

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