Answer to Question #2932 in Inorganic Chemistry for christina
How to calculate the ph of an acid?
<br>H3PO4 ---------> H2PO4- + (H+) Ka1 = 7.5x10^-3
<br>H2PO4- --------> HPO4-2 + (H+) Ka2 = 6.2x10^-8
<br>HPO4 -2 -------> PO4 -3 + (H+) Ka3 = 4.8x10^-13
<br>calculate the ph of one molar solution of H3PO4 that is completely ionized? (by using the 3 equation to find the pH) . How different will be the ph from irregular calculation (which is by using the first equation to find the pH).
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