Answer to Question #2692 in Inorganic Chemistry for Charlow
ν (N) = 0.483g/14 g/mol = 0.0345 mol
ν (O) = 1.104g/ 16 g/mol = 0.069 mol.
N : O = 0.0345 : 0.069 = 1 : 2.
The empirical formula of the compound is NO2.
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