Answer to Question #22095 in Inorganic Chemistry for khadijah
If 10.00 g of magnesium is reacted with 95.75 g of copper (II) sulphate, magnesium sulphate and copper are formed.
a. Which reactant is in excess?
b. Calculate the mass of copper formed.
Mg + CuSO4 = MgSO4 + Cu
n(Mg) = m/M
M(Mg) = 24 g/mol
n(Mg) = 10g/24g/mol = 0.417 mol
n(CuSO4) = m/M
M(CuSO4)= 64 + 32 + 16*4 = 160 g/mol
n(CnSO4) = 97.75g/160g/mol = 0.61 mol
a. Cu is in excess
n(Cu)formed = 0.417 mol
m(Cu)formed = 0.417mol*64g/mol = 26.68 g
b. The mass of copper formed = 26.68 g