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Answer to Question #22094 in Inorganic Chemistry for khadijah

Question #22094
Zinc reacts with hydrochloric acid based on the following equation:


If 150 g of Zn reacts with 73 g of HCl:

a. Which reactant is the limiting reagent?
b. What mass of ZnCl2 would be produced?
Expert's answer

Zinc reacts with hydrochloric acid based on the following equation

If 150 g of Zn reacts with 73 g of HCl:

a. Which reactant is the limiting reagent?

b. What mass of ZnCl2 would be produced?

Zn + 2HCl = ZnCl2 + H2

n(Zn) = m/M

n(Zn) = 150g/65g/mol = 2,3 mol

n(HCl) = 73g/35,5 g/mol = 2 mol

the limiting reagent in this reaction - HCl, because it isin excess

n(Zn) react = 1 mol

n(ZnCl2) = 1 mol

m(ZnCl2) = M*n

M(ZnCl2) = 65 + 35,5*2 = 136 g/mol

m(ZnCl2) = 136 g/mol * 1 mol = 136 g

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Comments

djkkikiFeRn420
28.05.17, 21:47

thc

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