Question #194390

The rate of a standard reaction is 0.00543 M/s at 40 oC. What will the rate be if the temperature is doubled?

A. 0.0109 M/s

B. 0.0217 M/s

C. 0.0434 M/s

D. 0.0869 M/s

E. All of the Above

Expert's answer

"R_1 = 0.00543 \\\\\n\nT_1 = 40 + 273 = 313 \\;K \\\\\n\nT_2 = 80 +273 = 353 \\;K \\\\\n\n\\frac{R_2}{R_1} = Q_{10}^{ \\frac{T_2-T_1}{10}}"

For most biological systems Q_{10} is from 2 to 3.

Suppose "Q_{10} = 2"

"\\frac{R_2}{0.00543} = 2^{ \\frac{353-313}{10}}\\\\\n\n\\frac{R_2}{0.00543} = 2^{ 4} \\\\\n\n\\frac{R_2}{0.00543} = 16 \\\\\n\nR_2 = 0.00543 \\times 16 = 0.0869"

Answer: D. 0.0869 M/s

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Assignment Expert19.05.21, 09:36Dear Lara,

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lara19.05.21, 04:00thank you so much

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