Answer to Question #194388 in General Chemistry for lara

Question #194388

Use the following information: A container has 8360.0 torr of Nitrogen, 5.000 atm of Oxygen, 101.3 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.


What is the mole fraction of Oxygen?


A. 0.1673

B. 0.2670

C. 0.2778

D. 0.4675

E. 0.5782



1
Expert's answer
2021-05-18T06:23:02-0400

8360 torr x 1 atm/760 torr = 11 atm N2

5 atm O2

101.1 kPa x 1 atm/101.32 = 0.998 atm Ar

760 mm Hg x 1 atm/760 mm Hg = 1 atm CO2

Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm 

mole fraction O2 = 5 atm/17.998 = 0.2778 (C)


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Comments

Assignment Expert
19.05.21, 09:35

Dear Lara,

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lara
19.05.21, 03:58

thank you so much

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