Question #194388

Use the following information: A container has 8360.0 torr of Nitrogen, 5.000 atm of Oxygen, 101.3 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.

What is the mole fraction of Oxygen?

A. 0.1673

B. 0.2670

C. 0.2778

D. 0.4675

E. 0.5782

Expert's answer

8360 torr x 1 atm/760 torr = 11 atm N_{2}

5 atm O_{2}

101.1 kPa x 1 atm/101.32 = 0.998 atm Ar

760 mm Hg x 1 atm/760 mm Hg = 1 atm CO_{2}

Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm

mole fraction O_{2} = 5 atm/17.998 = 0.2778 (C)

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Assignment Expert19.05.21, 09:35Dear Lara,

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