Answer to Question #173645 in General Chemistry for Sophia

Question #173645

When copper (II) chloride reacts with sodium nitrate, copper (II) nitrate and sodium chloride are formed


A. Write the balanced equation for the reaction given above:

_CuCI2+_NaNO3 = _Cu(NO3)2+_ NaCI


B. If 15 grams of copper (II) chloride react with 20.0 grams of sodium nitrate, how much sodium chloride can be formed?


Grams of NaCI(15.0g CuCI) I =


Grams of NaCI( 20.0g NaNO3)=


C. What is the limiting Reagent for the reaction?(chemical formula)


D. How many grams of copper (II) nitrate If formed? (Numbers only)


E. How much of the excess reagent is left over in this reaction? (Question D) numbers only


F. If 11.3 grams of sodium chloride are formed in the reaction described in problem B, what is the percent yield of this reaction?


1
Expert's answer
2021-03-22T06:39:36-0400

"a) CuCI_2+2NaNO_3=Cu(NO3)_2+2NaCI"

b) "m(NaCl)=m(CuCI2)\u00d72Mr(NaCl)\/Mr(CuCI2)=15\u00d72\u00d7(94\/135) =20.89 g"


c) "CuCI_2" - limiting reactant;


"NaNO_3" - excess reactant


d)"mleft(NaNO_3)=20 - (15\u00d7170\/135)=1.1 g"


e) "Cu(NO3)_2=0.92\u00d715\u00d7188\/135=19.22 g"


f) "65.7\\%"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS