In a redox reaction, 100ml groundwater with 150ml sulfuric acid was titrated with 6.5 x 10-6 mol l-1 concentrated potassium permanganate (IIV). The volume of KMnO4- used is 26.5ml. What is the concentration of the Fe (II) in the water? The redox equation for this reaction is: MnO4- + 5Fe2+ + 8H+ --- > 5Fe3+ + Mn2+ + 4H2O From the equation, it is clear that the ratio of MnO4- and Fe2+ is 1:5
From my working, I received the concentration to be 3.45 x 10-6 mol l-1 of Fe2+. Is this correct?
Yes it is correct
Comments
Leave a comment