Answer to Question #187828 in Molecular Biology for FAIZAN KHAN

Question #187828

    A DNA molecule with a length of 5000 base pairs (bp). treated separately with restriction enzymes A and B.

Restrictase A cut DNA into 4 fragments of 2100, 1400, 1000, and 500 bp. Restrictase B gave 3 fragments: 2500, 1300, and 1200 bp.

       Processing of the studied fragment simultaneously with two restriction enzymes gave 6 fragments: 1900, 1000, 800, 600, 500, 200 bp.

      A restriction map of this DNA fragment is presented. Using the restriction data of enzymes A and B, simulate restriction mapping by matching the restriction map of the DNA fragment to this map.    

Expert's answer

Restriction enzymes (originally isolated from bacteria) cut double-stranded DNA at particular nucleotide sequences into fragments, usually four, five, or six nucleotides long. A restriction enzyme will cleave the DNA wherever the particular recognition sequence (or restriction site) of the enzyme occurs.

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