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# Answer to Question #22427 in Perl for Sandeep Saxena

Question #22427
Ques 1:
my $a == &lt;stdin&gt;; #if input is given Pardeep then what is the output of following script? if($a == &quot;Pardeep&quot;)
{
print &quot;match&quot;;
}
elsif($a == &quot;pardeep&quot;) { print &quot;ok&quot; } else{ print &quot;not match&quot;; } a)match b)not match c)ok d)none Ques 2: our$a = 8;
our $b = 7; sub first { my$a =4;
local $b = 9; &second; } print &quot;$b &quot;;

sub second
{
print $a; print$b;
}
&first;

what is the result of above print command?

a)8
b)7
c)4
d)9
1
2013-01-21T10:00:53-0500
Question 1:
a) match

However, the first command
my $a ==<stdin>; does not assign to$a the value from stdin, since herecomparison operator "==" is used instead of "="
Moreover, in if/elseif/else statement it is usedNUMERICAL comparison operator "=="
is used for comparing strings.
In this case boths strings $a and "Pardeep" areconverted to zeros 0, and then these zeros are compared. As they are equal, ($a =="Pardeep")
is true, and so the program prints "match"

If we'd use "eq" instead of "==": if($a eq"Pardeep") { print"match"; } elsif($a eq"pardeep")
{
print"ok"
}
else
{
print"not match";
}

then the output will be "not match"Ques 2:The print command
print " $b"; will print the value of$b defined at line
our $b = 7; since in true subroutine "first" the variable$bwith the same name is defined as "local"
So the correct answer is b) 7

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