Answer to Question #22427 in Perl for Sandeep Saxena

Question #22427
Ques 1: my $a == <stdin>; #if input is given Pardeep then what is the output of following script? if($a == "Pardeep") { print "match"; } elsif($a == "pardeep") { print "ok" } else{ print "not match"; } a)match b)not match c)ok d)none Ques 2: our $a = 8; our $b = 7; sub first { my $a =4; local $b = 9; &second; } print " $b "; sub second { print $a; print$b; } &first; what is the result of above print command? a)8 b)7 c)4 d)9
Expert's answer
Question 1:
correct answer is
a) match

However, the first command
my $a ==<stdin>;
does not assign to $a the value from stdin, since herecomparison operator "==" is used instead of "="
Moreover, in if/elseif/else statement it is usedNUMERICAL comparison operator "=="
is used for comparing strings.
In this case boths strings $a and "Pardeep" areconverted to zeros 0, and then these zeros are compared.
As they are equal,
($a =="Pardeep")
is true, and so the program prints "match"

If we'd use "eq" instead of "==": if($a eq"Pardeep")
{
print"match";
}
elsif($a eq"pardeep")
{
print"ok"
}
else
{
print"not match";
}

then the output will be "not match"Ques 2:The print command
print " $b";
will print the value of $b defined at line
our $b = 7;
since in true subroutine "first" the variable $bwith the same name is defined as "local"
So the correct answer is b) 7

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