Answer to Question #90923 in Molecular Physics | Thermodynamics for minh tâm

Question

Calculate the change in entropy when 12g of water at -10oC is raised to 100oC and convert to steam at 100oC. Assume that specific heat of water cwater = 4190 J·g-1·K-1, heat of vaporization Lv = 2256 kJ/kg, specific heat of ice cice = 2220 J·g-1·K-1, heat of fusion LF = 334 kJ/kg.

Answer 1

The total entropy change is:

$$Q = m * (c_i* \Delta T_1 + H_f + c_w*\Delta T_2 + H_v)$$

$$Q = 12 * (2220*10 + 334 + 4190*100 + 2256)$$

$$Q = 5325 (kJ)$$