One kg of a steam with quality of 20 percent is heated at a constant pressure of 200kPa until the temperature reaches 400°C. Calculate the work done by the system.
Why did not you get Vf value at 200kPa to find V1? And why did not you
consider about 20%? At 200kPa stage, ther are a gas volume and a fluid
volume as well. My Answer is... GAS VOLUME @ 200kPa = 0.2*Vg*1kg FLUID
VOLUME @ 200kPa = 0.8*Vf*1kg hence:- V2-V1 =1.5493-(0.2*Vg+0.8*Vf)
WORK =1* 200000*(1.5493- (0.17714+0.000488)) =274.3344kJ
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Why did not you get Vf value at 200kPa to find V1? And why did not you consider about 20%? At 200kPa stage, ther are a gas volume and a fluid volume as well. My Answer is... GAS VOLUME @ 200kPa = 0.2*Vg*1kg FLUID VOLUME @ 200kPa = 0.8*Vf*1kg hence:- V2-V1 =1.5493-(0.2*Vg+0.8*Vf) WORK =1* 200000*(1.5493- (0.17714+0.000488)) =274.3344kJ
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