Question #1634

How many grams of steam at 110 C must be added to 1kg of ice a 0 C to melt it without raising its temperature?

Expert's answer

Specific heat of ice fusion: 333.55 kJ/kg

Specific heat of water vaporization: 2256 kJ/kg

Specific heat capacity of steam: 1.996 kJ/kg

Let's write the heat equation:

333.55[kJ/kg]*1[kg] = 1.996[kJ/kgK]*(110-100)[K]*m + 2256 kJ/kg*m

therefore

m = 333.55/2275.96 = 0.1466 kg = 146.6 [g]

Specific heat of water vaporization: 2256 kJ/kg

Specific heat capacity of steam: 1.996 kJ/kg

Let's write the heat equation:

333.55[kJ/kg]*1[kg] = 1.996[kJ/kgK]*(110-100)[K]*m + 2256 kJ/kg*m

therefore

m = 333.55/2275.96 = 0.1466 kg = 146.6 [g]

## Comments

122345625.02.11, 19:48what formula did you use for this equation

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