A shopper in a supermarket pushes a cart
with a force of 38 N directed at an angle of
26.4◦ downward from the horizontal.
Find the work done by the shopper as she
moves down a 49.2 m length of aisle.
Answer in units of kJ.
1
Expert's answer
2010-10-05T09:59:21-0400
As you know work is the force multiplies the distance. In this case we need consider only the horizontal component of force Fh=F*sin α=38*sin 26.4=16.9 because there no any moving in vertical plane. Then the work is A=Fh*l=16.9*49.2=831J=0.83kJ
work A=F*S where F- projection of the force on the direction of motion
s-way trawelled while force is actiong Hence in our case
F=39N*cos(29°) Work A=39N*cos(29°)*50m=1705,5 J
Sabrina
08.11.11, 20:36
A shopper in a supermarket pushes a cart with a force of 39.0 N
directed at an angle of 29.0° downward from the horizontal. Find the
work done by the shopper on the cart as he moves down an aisle 50.0 m
long.
Leave a comment
Thank you! Your comments have been successfully added. However, they need to be checked by the moderator before being published.
Comments
work A=F*S where F- projection of the force on the direction of motion s-way trawelled while force is actiong Hence in our case F=39N*cos(29°) Work A=39N*cos(29°)*50m=1705,5 J
A shopper in a supermarket pushes a cart with a force of 39.0 N directed at an angle of 29.0° downward from the horizontal. Find the work done by the shopper on the cart as he moves down an aisle 50.0 m long.
Leave a comment