# Answer to Question #725 in Mechanics | Relativity for Brian

Question #725

A shopper in a supermarket pushes a cart
with a force of 38 N directed at an angle of
26.4◦ downward from the horizontal.
Find the work done by the shopper as she
moves down a 49.2 m length of aisle.
Answer in units of kJ.

Expert's answer

As you know work is the force multiplies the distance.

In this case we need consider only the horizontal component of force

Fh=F*sin α=38*sin 26.4=16.9

because there no any moving in vertical plane.

Then the work is A=Fh*l=16.9*49.2=831J=0.83kJ

Answer 0.83kJ

In this case we need consider only the horizontal component of force

Fh=F*sin α=38*sin 26.4=16.9

because there no any moving in vertical plane.

Then the work is A=Fh*l=16.9*49.2=831J=0.83kJ

Answer 0.83kJ

## Comments

Assignment Expert10.11.11, 15:16work A=F*S where F- projection of the force on the direction of motion

s-way trawelled while force is actiong

Hence in our case F=39N*cos(29°)

Work A=39N*cos(29°)*50m=1705,5 J

Sabrina08.11.11, 20:36A shopper in a supermarket pushes a cart with a force of 39.0 N directed at an angle of 29.0° downward from the horizontal. Find the work done by the shopper on the cart as he moves down an aisle 50.0 m long.

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