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Answer to Question #725 in Mechanics | Relativity for Brian
Question #725
A shopper in a supermarket pushes a cart
with a force of 38 N directed at an angle of
26.4◦ downward from the horizontal.
Find the work done by the shopper as she
moves down a 49.2 m length of aisle.
Answer in units of kJ.
with a force of 38 N directed at an angle of
26.4◦ downward from the horizontal.
Find the work done by the shopper as she
moves down a 49.2 m length of aisle.
Answer in units of kJ.
Expert's answer
As you know work is the force multiplies the distance.
In this case we need consider only the horizontal component of force
Fh=F*sin α=38*sin 26.4=16.9
because there no any moving in vertical plane.
Then the work is A=Fh*l=16.9*49.2=831J=0.83kJ
Answer 0.83kJ
In this case we need consider only the horizontal component of force
Fh=F*sin α=38*sin 26.4=16.9
because there no any moving in vertical plane.
Then the work is A=Fh*l=16.9*49.2=831J=0.83kJ
Answer 0.83kJ
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Comments
work A=F*S where F- projection of the force on the direction of motion s-way trawelled while force is actiong Hence in our case F=39N*cos(29°) Work A=39N*cos(29°)*50m=1705,5 J
A shopper in a supermarket pushes a cart with a force of 39.0 N directed at an angle of 29.0° downward from the horizontal. Find the work done by the shopper on the cart as he moves down an aisle 50.0 m long.
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