Question #724

A rain cloud contains 3.36 × 107 kg of water
vapor.
The acceleration of gravity is 9.8 m/s2 .
How long would it take for a 3.6 kW pump
to lift the same amount of water to an altitude
of 17000 m?
Answer in units of years.

Expert's answer

The total work of lifting same amount of water is:

A=m*g*h=33,600,000*9.8*17,000=177.5kW*year.

And this work is equal to power*time:

A=W*t => t=A/W=177.5/3.6=49.3 years

Answer 49.3 years

A=m*g*h=33,600,000*9.8*17,000=177.5kW*year.

And this work is equal to power*time:

A=W*t => t=A/W=177.5/3.6=49.3 years

Answer 49.3 years

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