Answer to Question #724 in Mechanics | Relativity for Brian
Question #724
A rain cloud contains 3.36 × 107 kg of water
vapor.
The acceleration of gravity is 9.8 m/s2 .
How long would it take for a 3.6 kW pump
to lift the same amount of water to an altitude
of 17000 m?
Answer in units of years.
vapor.
The acceleration of gravity is 9.8 m/s2 .
How long would it take for a 3.6 kW pump
to lift the same amount of water to an altitude
of 17000 m?
Answer in units of years.
Expert's answer
The total work of lifting same amount of water is:
A=m*g*h=33,600,000*9.8*17,000=177.5kW*year.
And this work is equal to power*time:
A=W*t => t=A/W=177.5/3.6=49.3 years
Answer 49.3 years
A=m*g*h=33,600,000*9.8*17,000=177.5kW*year.
And this work is equal to power*time:
A=W*t => t=A/W=177.5/3.6=49.3 years
Answer 49.3 years
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