Answer to Question #6388 in Mechanics | Relativity for alex ruiz

Question

if the unbalance force on the ball is 7.25*10^-2n and 4.35*10^-2j of work is done to lift the ball how far does the catcher lift the ball?

Answer 1

by defenition of work A=F*d, where A - is work, F - forse, d - distance. Then we
have: d=A/F=4.35*10^-2j/7.25*10^-2n=0,6 metres.