Question #6388

if the unbalance force on the ball is 7.25*10^-2n and 4.35*10^-2j of work is done to lift the ball how far does the catcher lift the ball?

Expert's answer

by defenition of work A=F*d, where A - is work, F - forse, d - distance. Then we

have: d=A/F=4.35*10^-2j/7.25*10^-2n=0,6 metres.

have: d=A/F=4.35*10^-2j/7.25*10^-2n=0,6 metres.

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