# Answer on Mechanics | Relativity Question for Jessica

Question #6351

A 98.0 N grocery cart is pushed 12.0 m along an aisle by a shopper who exerts a constant horizontal foce of 40.0 N. If all frictional forces are neglected and the cart starts from rest, what is the grocery cart's final speed?

Expert's answer

As the acceleration of gravity g = 9.8 m/s^2, then the mass of cart is

m =

98/9,8 = 10 kg.

Using the Newton's Second Law

F = ma. So, the cart's

acceleration is a = F/m = 40/10 = 4 m/s^2.

As the initial speed was zero, we

get the equation for displacement and final speed:

S = a*t^2/2, V = at.

t

= sqrt(2*S/a).

V = a*sqrt(2*S/a) = sqrt(2*S*a) = sqrt(2*12*4) = sqrt(96) =

9.8 m/s.

m =

98/9,8 = 10 kg.

Using the Newton's Second Law

F = ma. So, the cart's

acceleration is a = F/m = 40/10 = 4 m/s^2.

As the initial speed was zero, we

get the equation for displacement and final speed:

S = a*t^2/2, V = at.

t

= sqrt(2*S/a).

V = a*sqrt(2*S/a) = sqrt(2*S*a) = sqrt(2*12*4) = sqrt(96) =

9.8 m/s.

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment