# Answer to Question #60593 in Mechanics | Relativity for Sakura

Question #60593

A satellite is placed in a circular orbit around Jupiter. The altitude of the satellite above the surface of Jupiter is 775km. Jupiter has a mass of 1.90x10^27kg and a radius of 7.14x10^7m.

1.Determine the radius of motion of the satellite.

2.What force is providing the centripetal force necessary for the satellite to stay in orbit?

3.In what direction is the centripetal force always acting?

4.Using the equation for centripetal force, Fc= m(v/R), and the gravitational force, Fg=Gmm/R^2, derive the mathematical equation that allows you to calculate the orbital speed of the satellite.

5.Calculate the orbital speed of the satellite circling Jupiter using the equation derived in part 3. The value of G=6.67x10^-11N*m^2/kg^2.

1.Determine the radius of motion of the satellite.

2.What force is providing the centripetal force necessary for the satellite to stay in orbit?

3.In what direction is the centripetal force always acting?

4.Using the equation for centripetal force, Fc= m(v/R), and the gravitational force, Fg=Gmm/R^2, derive the mathematical equation that allows you to calculate the orbital speed of the satellite.

5.Calculate the orbital speed of the satellite circling Jupiter using the equation derived in part 3. The value of G=6.67x10^-11N*m^2/kg^2.

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## Comments

Assignment Expert11.05.18, 22:29Dear Jek, h is the altitude of the satellite above the surface of Jupiter (775km).

Jek11.05.18, 20:48In q4 where did the h come from?

Crystal01.07.16, 05:40Thank you

Assignment Expert30.06.16, 17:28775 km = 775*10^3 m = 0.0775*10^7 m

R = (0.0775 + 7.14)*10^7 m = 7.2175*10^7 m

Sakura29.06.16, 18:48I don't understand how you get 72175x10^7m in question because every time I try it, I calculate 7.82x10^9m.

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