Answer to Question #5127 in Mechanics | Relativity for Kristen
Two rocks are thrown off the edge of a cliff that is 15.0 m above the ground. The first rock is thrown upward, at a velocity of +12.0 m/s. The second is thrown downward, at a velocity of −12.0 m/s. Ignore air resistance. Determine (a) how long it takes the first rock to hit the ground and (b) at what velocity it hits. Determine (c) how long it takes the second rock to hit the ground and (d) at what velocity it hits.
a) S=[img width=14,height=20]file:///C:/Users/Sekventa/AppData/Local/Temp/OICE_B5A94EB8-5E00-4A5C-AF4E-5C45A3C9F209.0/msohtmlclip1/01/clip_image002.gif[/img]V0t+gt^2/2 15=12t+5t^2 5t^2+12t-15=0
b) V=V0+gt=12+0.9*10=21m/s c) V0=gt t=V0/g=1.2 s it flies upwards
all time is equal to sum 2.1 sec+ 1.2 sec =3.3sec d)V=V0+gt here V0=0 V=gt=3.3*10=33m/s