# Answer on Mechanics | Relativity Question for Kristen

Question #5127

Two rocks are thrown off the edge of a cliff that is 15.0 m above the ground. The first rock is thrown upward, at a velocity of +12.0 m/s. The second is thrown downward, at a velocity of −12.0 m/s. Ignore air resistance. Determine (a) how long it takes the first rock to hit the ground and (b) at what velocity it hits. Determine (c) how long it takes the second rock to hit the ground and (d) at what velocity it hits.

Expert's answer

a) S=[img width=14,height=20]file:///C:/Users/Sekventa/AppData/Local/Temp/OICE_B5A94EB8-5E00-4A5C-AF4E-5C45A3C9F209.0/msohtmlclip1/01/clip_image002.gif[/img]V

15=12t+5t^2

5t^2+12t-15=0

b)

V=V

c) V

t=V

and again

all time is equal to sum 2.1 sec+ 1.2 sec =3.3sec

d)V=V

V=gt=3.3*10=33m/s

_{0}t+gt^2/215=12t+5t^2

5t^2+12t-15=0

b)

V=V

_{0}+gt=12+0.9*10=21m/sc) V

_{0}=gtt=V

_{0}/g=1.2 s it flies upwardsand again

all time is equal to sum 2.1 sec+ 1.2 sec =3.3sec

d)V=V

_{0}+gt here V_{0}=0V=gt=3.3*10=33m/s

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