# Answer to Question #5097 in Mechanics | Relativity for Sam

Question #5097

A 710 spacecraft has total energy -0.58 and is in circular orbit around the Sun. Find (a) its orbital radius, (b) its kinetic energy, and (c) its speed

Expert's answer

E=Ek+Ep

Ek=(mv^2)/2

Ep=mgR

m=710

E=0.58

a)

E=mgR+(mv^2)/2

R=((mv^2)/2-E)/mg

b)

Ek=E-Ep=E-mgR

c)

E=mgR+(mv^2)/2

v=sqrt(2(E-mgR)/m^2)

Ek=(mv^2)/2

Ep=mgR

m=710

E=0.58

a)

E=mgR+(mv^2)/2

R=((mv^2)/2-E)/mg

b)

Ek=E-Ep=E-mgR

c)

E=mgR+(mv^2)/2

v=sqrt(2(E-mgR)/m^2)

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