Answer to Question #44668 in Mechanics | Relativity for Anurag Singh

Question #44668
1.The velocity of a particle moving on the x -axis is given by v = x^2 + x, where 'x' is in m and 'v' is in m/s What is the position (in meters) when it's acceleration is 30 m/(s^2)? 2. A boy standing on the top of a tower of height 54 ft. throws a packet with a speed of 20 ft./s directly aiming for his friend who is standing 72 ft. away from the foot of the tower. The packet falls short of the friend on the ground by X*16/3. The value X is _______ .
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Expert's answer
2014-08-05T03:43:56-0400
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Assignment Expert
11.08.14, 18:29

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Anurag Singh
11.08.14, 09:16

Thank you very much, Sir !!!

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