Answer to Question #4361 in Mechanics | Relativity for Nate
(a) Find the speed at which the ball was launched. (Give your answer to two decimal places to reduce rounding errors in later parts.)
We know that at the moment t=2.2 the ball is 7.5 highover the ground.
7.5=2.2v0 sin(teta)-4.84g/2= 2.2v0 sin(53)-4.84g/2=1.757v0-23.716 => v0=17.77 m/s[img width=624,height=56]file:///C:/Users/Sekventa/AppData/Local/Temp/OICE_18DAB834-6E09-410E-9CBC-2259ACB05FA0.0/msohtmlclip1/01/clip_image004.png[/img]
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