Answer to Question #4344 in Mechanics | Relativity for Tim Ferid

Question #4344
A ball is thrown vertically upwards and travels freely under gravity. Three seconds later it has a speed of 4.4 ms-1 but its direction has changed. Find the initial velocity of the particle, can I see working as well?
1
Expert's answer
2011-10-14T08:59:04-0400
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h0=v0t-gt0^2/2
h1=h0+gt1^2/2
t0+t1=3
v1=sqrt(2gh1)
t1=sqrt(2h1/g)

h0=v0*(3-t1)-g*(3-t1)^2/2
h1=v0*(3-t1)-g*(3-t1)^2/2+gt1^2/2
t0=3-t1
h1=v1^2/2g
t1=sqrt(2v1^2/2g^2)

v1^2/2g=v0*(3-t1)-g*(3-t1)^2/2+gt1^2/2
t1=v1/g

t1=0.45

v0=12.02 m/s

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