Answer to Question #4270 in Mechanics | Relativity for valeria
parallelogram build on A and B. (By definition)
Thus, the area of that parallelogram is |S|=|AxB|
On the other hand this area can be obtained as cos(a)|A||B|, where ‘a’ is the angle between A and B.
Then we can get cos(a):
Cos(a) = |AxB|/(|A||B|)
Cos(a) = (4.90^2+2.00^2)^0.5/(2.96*3.08)=0.58051591
A = acos(0.58051591) = 54.51316281 degrees
Thus, the approximate value is 54.5 degrees.
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