The position(x) of a body moving along x-axix at time (t) is given by x=3t2,where x is in metre and time t is in second.If mass of the body is 2kg ,then find the instantaneous power delivered to body by force acting on it at t=4sec.
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Expert's answer
2011-09-30T10:38:45-0400
The position(x) of a body moving along x-axix at time (t) is given by x=3t^2,where x is in metre and time t is in second.If mass of the body is 2kg ,then find the instantaneous power delivered to body by force acting on it at t=4sec.
Solution. First notice that & velocity of a body, & v = x' = 6t m/s & acceleration of a body, a = v' = 6 m/s^2 Hence the force acting on the body is F = ma = 2 * 6 = 12 N
Since F is constant, then the work of this force to move the body from the point& 0& to& x& is equal to
A = F x,
whence the instantaneous power delivered to body by force is
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