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Answer to Question #42023 in Mechanics | Relativity for qwerty

Question #42023
A NUMBER OF TUNING FORKS ARE ARRANGED IN ORDER OF INCREASING FREQUENCY AND ANY 2 SUCCESSIVE TUNING FORKS PRODUCE 4BEATS/S WHEN SOUNDED TOGETHER. IF THE LAST TUNING FORK HAS A FREQUENCY OCTAVE HIGHER THAN THE FIRST AND FREQUENCY OF THE FIRST IS 256 Hz. THEN THE NUMBER OF TUNING FORKS IS :
1. 63
2. 64
3. 65
4. 66
Expert's answer
The frequency of the last tuningfork octave higher than the first one of a frequency 226 Hz. So, it equals 512
Hz. Thus, the number of tuning forces is
(512-256)/4 = 64. 

Answer is 2. 64 tuning forces.

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Comments

Assignment Expert
14.10.18, 20:43

Dear visitor,
please use panel for submitting new questions

Prashant
12.10.18, 10:08

Sir send the full solution.... that how we get 226 hz.. in your ans.

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