Answer to Question #42019 in Mechanics | Relativity for Tanya

Question #42019
Hey And its,a physics ques From laws of motion-motion in connected bodies There was a,ques of 2 bodies suspended from a pully m1>m2 with acceleration a Find a And tension Ans was a=(m1-m2)g/(m1+m2) And T=2m1m2g/(m1+m2) For mass m1 T=m1g-m1a (i) For m2 T =m2a+m2g My doubt Why acc is taken in opp dir.? Since in m1 acc is downward thus eqn should be For mass m1 T=m1g+m1a (i) and for m2 acc is upward T =m2g-m2a Then f=ma is taken opp In direction When it is along the direction of mg in m1 case and along t in m2 case
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Expert's answer
2014-05-07T10:03:08-0400
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