# Answer to Question #42019 in Mechanics | Relativity for Tanya

Question #42019

Hey

And its,a physics ques

From laws of motion-motion in connected bodies

There was a,ques of 2 bodies suspended from a pully m1>m2 with acceleration a

Find a

And tension

Ans was a=(m1-m2)g/(m1+m2)

And T=2m1m2g/(m1+m2)

For mass m1

T=m1g-m1a (i)

For m2

T =m2a+m2g

My doubt

Why acc is taken in opp dir.?

Since in m1 acc is downward thus eqn should be

For mass m1

T=m1g+m1a (i)

and for m2 acc is upward

T =m2g-m2a

Then f=ma is taken opp

In direction

When it is along the direction of mg in m1 case and along t in m2 case

And its,a physics ques

From laws of motion-motion in connected bodies

There was a,ques of 2 bodies suspended from a pully m1>m2 with acceleration a

Find a

And tension

Ans was a=(m1-m2)g/(m1+m2)

And T=2m1m2g/(m1+m2)

For mass m1

T=m1g-m1a (i)

For m2

T =m2a+m2g

My doubt

Why acc is taken in opp dir.?

Since in m1 acc is downward thus eqn should be

For mass m1

T=m1g+m1a (i)

and for m2 acc is upward

T =m2g-m2a

Then f=ma is taken opp

In direction

When it is along the direction of mg in m1 case and along t in m2 case

Expert's answer

## Comments

## Leave a comment